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Question
In ΔPQR, PS ⊥ QR ; prove that: PQ > QS and PR > PS
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Solution
In ΔPQS,
PS ⊥ QR ....(Given)
PS < PR ....(Of all the straight lines that can be drawn to a given straight line from a point outside it, the perpendicular is the shortest.)
I.e. PR > PS.
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