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Question
In the given figure, ∠B < ∠A and ∠C < ∠D. Show that AD < BC.
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Solution
In ΔAOB,
∠B < ∠A
⇒ AO < BO (Side opposite to smaller angle is smaller) ... (1)
In ΔCOD,
∠C < ∠D
⇒ OD < OC (Side opposite to smaller angle is smaller) ... (2)
On adding equations (1) and (2), we obtain
AO + OD < BO + OC
AD < BC
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