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In how many ways can the letters of the word PERMUTATIONS be arranged if the words start with P and end with S. - Mathematics

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Question

In how many ways can the letters of the word PERMUTATIONS be arranged if the words start with P and end with S.

Sum
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Solution

The word PERMUTATIONS has a total 12 letters, in which T – 2, rest all are different.

The positions of P and S have been fixed.

Hence, in this case, required number of arrangements  

= `(10!)/(2!)` = 1814400.

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Chapter 6: Permutations and Combinations - EXERCISE 6.3 [Page 114]

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NCERT Mathematics [English] Class 11
Chapter 6 Permutations and Combinations
EXERCISE 6.3 | Q 11. (i) | Page 114

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