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In how many ways can the letters of the word PERMUTATIONS be arranged if the words start with P and end with S. - Mathematics

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Question

In how many ways can the letters of the word PERMUTATIONS be arranged if the words start with P and end with S.

Sum
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Solution

The word PERMUTATIONS has a total 12 letters, in which T – 2, rest all are different.

The positions of P and S have been fixed.

Hence, in this case, required number of arrangements  

= `(10!)/(2!)` = 1814400.

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Chapter 7: Permutations and Combinations - Exercise 7.3 [Page 148]

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NCERT Mathematics [English] Class 11
Chapter 7 Permutations and Combinations
Exercise 7.3 | Q 11.1 | Page 148

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