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Tamil Nadu Board of Secondary EducationHSC Science Class 11

Find the sum of all 4-digit numbers that can be formed using digits 1, 2, 3, 4, and 5 repetitions not allowed?

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Question

Find the sum of all 4-digit numbers that can be formed using digits 1, 2, 3, 4, and 5 repetitions not allowed?

Sum
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Solution

The given numbers are 1, 2, 3, 4, 5

The total number of arrangements.

Using the digits 1, 2, 3, 4 and 5 taking 4 at a time is 5P4

= 5 × 4 × 3 × 2

= 120

∴ 120 four-digit numbers can be formed using the given 5 digits without repetition.

To find the sum of these numbers.

We will find the sum of digits at unit’s, ten’s, hundred’s and thousand’s place in all these 120 numbers.

Consider the digit in unit’s place. In all these numbers

Each of these digits 1, 2, 3, 4, 5 occurs 120 in `120/5`

= 24 times in the units place

∴ The sum of the digits at unit’s place

= 24(1 + 2 + 3 + 4 + 5)

= 24 × 15

= 360

Similarly sum of the digit’s at ten’s place = 360

Sum of the digit’s at hundred’s place = 360

Sum of the digit’s at thousand’s place = 360

∴ Sum of all four digit numbers formed using the digit’s 1, 2, 3, 4, 5

= 360 × 10° + 360 × 101 + 360 × 102 + 360 × 103

= 360(10° + 101 + 102 + 103)

= 360(1 + 10 + 100 + 1000)

= 360 × 1111

= 3,99,960

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Chapter 4: Combinatorics and Mathematical Induction - Exercise 4.2 [Page 178]

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Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 11 TN Board
Chapter 4 Combinatorics and Mathematical Induction
Exercise 4.2 | Q 19 | Page 178

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