Advertisements
Advertisements
Question
- In how many ways can 8 identical beads be strung on a necklace?
- In how many ways can 8 boys form a ring?
Advertisements
Solution
- Number of ways 8 identical beads can be stringed by `((8 - 1)!)/2 = (7!)/2`
-
Number of ways 8 boys form a ring = (8 – 1)! = 7!
APPEARS IN
RELATED QUESTIONS
Find n if n – 1P3 : nP4 = 1 : 9
In how many ways can the letters of the word PERMUTATIONS be arranged if the there are always 4 letters between P and S?
Which of the following are true:
(2 × 3)! = 2! × 3!
A coin is tossed 8 times, how many different sequences of heads and tails are possible?
How many strings are there using the letters of the word INTERMEDIATE, if all the vowels are together
Each of the digits 1, 1, 2, 3, 3 and 4 is written on a separate card. The six cards are then laid out in a row to form a 6-digit number. How many distinct 6-digit numbers are there?
Choose the correct alternative:
The product of r consecutive positive integers is divisible b
How many words can be formed with the letters of the word MANAGEMENT by rearranging them?
Find the number of different words that can be formed from the letters of the word ‘TRIANGLE’ so that no vowels are together
In a certain city, all telephone numbers have six digits, the first two digits always being 41 or 42 or 46 or 62 or 64. How many telephone numbers have all six digits distinct?
