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Tamil Nadu Board of Secondary EducationHSC Science Class 11

Each of the digits 1, 1, 2, 3, 3 and 4 is written on a separate card. The six cards are then laid out in a row to form a 6-digit number. How many of these 6-digit numbers are divisible by 4? - Mathematics

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Question

Each of the digits 1, 1, 2, 3, 3 and 4 is written on a separate card. The six cards are then laid out in a row to form a 6-digit number. How many of these 6-digit numbers are divisible by 4?

Sum
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Solution

In order to get the 6-digit number divisible by 4

The last two digits must be divisible by 4

∴ The last two digits should be 12 or 24 or 32

        24
1 2 3 4 5

Let the last box be filled with 24.

The remaining 4 boxes can be filled with the remaining digits

1, 1, 3, 3 in `(4!)/(2! xx 2!)` ways.

        12
1 2 3 4 5

Let the last box be filled with 12.

The remaining 4 boxes can be filled with the remaining digits.

1, 3, 3, 4 in `(4!)/(2!)` ways

        32
1 2 3 4 5

Let the last box be filled with 32.

The remaining 4 boxes can be filled with the remaining digits

The total number of 6 digit numbers which are divisible by 4 is

= `(4!)/(2! xx 2!) + (4!)/(2!) + (4!)/(2!)`

= `(1 xx 2 xx 3 xx 4)/(1 xx 2 xx 1 xx 2) + (1 xx 2 xx 3 xx 4)/(1 xx 2) + (1 xx 2 xx 3 xx 4)/(1 xx 2)`

= 6 + 12 + 12

= 30

∴ Required number of 6-digit numbers = 30

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Chapter 4: Combinatorics and Mathematical Induction - Exercise 4.2 [Page 178]

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Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 11 TN Board
Chapter 4 Combinatorics and Mathematical Induction
Exercise 4.2 | Q 15. (iii) | Page 178

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