English

In a certain city, all telephone numbers have six digits, the first two digits always being 41 or 42 or 46 or 62 or 64. How many telephone numbers have all six digits distinct?

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Question

In a certain city, all telephone numbers have six digits, the first two digits always being 41 or 42 or 46 or 62 or 64. How many telephone numbers have all six digits distinct?

Sum
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Solution

If first two digits is 41, then the remaining 4 digits can be arranged in 8P4 ways

= `(8!)/((8 - 4)!)`

= `(8!)/(4!)`

= `(8 xx 7 xx 6 xx 5 xx 4!)/(4!)`

= 1680

Similarly, first two digits can be 42 or 46 or 62 or 64.

∴ Total number of telephone numbers have all digits distinct = 5 × 1680 = 8400

Hence, the required telephone numbers = 8400

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Chapter 7: Permutations and Combinations - Exercise [Page 123]

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NCERT Exemplar Mathematics Exemplar [English] Class 11
Chapter 7 Permutations and Combinations
Exercise | Q 18 | Page 123

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