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Using the digits 1, 2, 3, 4, 5, 6, 7, a number of 4 different digits is formed. Find C1 C2 (a) How many numbers are formed? (i) 840 (b) How many number are exactly divisible by 2? (i) 200 (c) How ma - Mathematics

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Question

Using the digits 1, 2, 3, 4, 5, 6, 7, a number of 4 different digits is formed. Find

C1 C2
(a) How many numbers are formed? (i) 840
(b) How many number are exactly divisible by 2? (i) 200
(c) How many numbers are exactly divisible by 25? (iii) 360
(d) How many of these are exactly divisible by 4? (iv) 40
Match the Columns
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Solution

C1 C2
(a) How many numbers are formed? (i) 840
(b) How many number are exactly divisible by 2? (i) 360
(c) How many numbers are exactly divisible by 25? (iii) 40
(d) How many of these are exactly divisible by 4? (iv) 200

Explanation:

(a) Total of 4 digit number formed with 1, 2, 3, 4, 5, 6, 7

= 7P4

= `(7 xx 6 xx 5 xx 4 xx 3!)/(3!)`

= 840

(b) When a number is divisible by 2

= 4 × 5 × 6 × 3

= 360

(c) Total numbers which are divisible by 25 = 40

(d) Total numbers which are divisible by 4 (last two digits is divisible by 4) = 200

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Chapter 7: Permutations and Combinations - Exercise [Page 128]

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NCERT Exemplar Mathematics [English] Class 11
Chapter 7 Permutations and Combinations
Exercise | Q 63 | Page 128

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