English
Tamil Nadu Board of Secondary EducationHSC Science Class 11

Three men have 4 coats, 5 waist coats and 6 caps. In how many ways can they wear them?

Advertisements
Advertisements

Question

Three men have 4 coats, 5 waist coats and 6 caps. In how many ways can they wear them?

Sum
Advertisements

Solution

Number of men = 3

Number of coats = 4

Number of waist coats = 5

Number of caps = 6

4 coats can be given to 3 men in 4P3 ways.

5 waist coats can be given to 3 men in 5P3 ways.

6 caps can be given to 3 men in 6P3 ways.

∴ Total number of ways of wearing 3 coats, 4 waist coats and 6 caps is

= 4P3 × 5P3 × 6P

= `(4)/((4 - 3)!) xx (5!)/((5 - 3)!) xx (6!)/((6 - 3)!)`

= `(4!)/(1!) xx (5!)/(2!)xx (6!)/(3!)`

= `(4 xx 3 xx 2 xx 1)/1 xx (5 xx 4 xx 3 xx 2 xx 1)/(2 xx 1) xx (6 xx 5 xx 4 xx 3!)/(3!)`

= 24 × 6 × 120

= 1,72,800

shaalaa.com
  Is there an error in this question or solution?
Chapter 4: Combinatorics and Mathematical Induction - Exercise 4.2 [Page 177]

APPEARS IN

Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 11 TN Board
Chapter 4 Combinatorics and Mathematical Induction
Exercise 4.2 | Q 3. (ii) | Page 177

RELATED QUESTIONS

Evaluate 4! – 3!


Is 3! + 4! = 7!?


In how many ways can the letters of the word PERMUTATIONS be arranged if the vowels are all together.


In how many ways can the letters of the word PERMUTATIONS be arranged if the there are always 4 letters between P and S?


Find x in each of the following:

\[\frac{1}{4!} + \frac{1}{5!} = \frac{x}{6!}\]

Find x in each of the following:

\[\frac{x}{10!} = \frac{1}{8!} + \frac{1}{9!}\]

Find x in each of the following:

\[\frac{1}{6!} + \frac{1}{7!} = \frac{x}{8!}\]

Find the number of ways in which one can post 5 letters in 7 letter boxes ?


In how many ways can 7 letters be posted in 4 letter boxes?


The number of arrangements of the word "DELHI" in which E precedes I is


The number of ways to arrange the letters of the word CHEESE are


If k + 5Pk + 1 =\[\frac{11 (k - 1)}{2}\]. k + 3Pk , then the values of k are


If (n+2)! = 60[(n–1)!], find n


The possible outcomes when a coin is tossed five times:


The number of ways to arrange the letters of the word “CHEESE”:


A test consists of 10 multiple choice questions. In how many ways can the test be answered if question number n has n + 1 choices?


How many strings are there using the letters of the word INTERMEDIATE, if the vowels and consonants are alternative


If the letters of the word FUNNY are permuted in all possible ways and the strings thus formed are arranged in the dictionary order, find the rank of the word FUNNY


Ten different letters of alphabet are given. Words with five letters are formed from these given letters. Then the number of words which have atleast one letter repeated is ______.


The number of permutations by taking all letters and keeping the vowels of the word ‘COMBINE’ in the odd places is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×