Advertisements
Advertisements
Question
A coin is tossed 8 times, how many different sequences of heads and tails are possible?
Advertisements
Solution
A coin on tossing has two outcomes.
Tossing a coin once number of outcomes = 2
∴ Tossing a coin 8 times number of outcomes = 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 = 28
∴ The different sequences of heads and tails are 28
APPEARS IN
RELATED QUESTIONS
Is 3! + 4! = 7!?
In how many ways can the letters of the word PERMUTATIONS be arranged if the there are always 4 letters between P and S?
Which of the following are true:
(2 × 3)! = 2! × 3!
In how many ways can three jobs I, II and III be assigned to three persons A, B and C if one person is assigned only one job and all are capable of doing each job?
How many numbers of four digits can be formed with the digits 1, 2, 3, 4, 5 if the digits can be repeated in the same number?
The number of permutations of n different things taking r at a time when 3 particular things are to be included is
Number of all four digit numbers having different digits formed of the digits 1, 2, 3, 4 and 5 and divisible by 4 is
The number of words that can be made by re-arranging the letters of the word APURBA so that vowels and consonants are alternate is
The number of different ways in which 8 persons can stand in a row so that between two particular persons A and B there are always two persons, is
If nP4 = 12(nP2), find n.
How many 6-digit telephone numbers can be constructed with the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 if each numbers starts with 35 and no digit appear more than once?
The greatest positive integer which divide n(n + 1) (n + 2) (n + 3) for all n ∈ N is:
The total number of 9 digit number which has all different digit is:
The number of words with or without meaning that can be formed using letters of the word “EQUATION”, with no repetition of letters is:
Three men have 4 coats, 5 waist coats and 6 caps. In how many ways can they wear them?
A test consists of 10 multiple choice questions. In how many ways can the test be answered if each question has four choices?
In how many ways 4 mathematics books, 3 physics books, 2 chemistry books and 1 biology book can be arranged on a shelf so that all books of the same subjects are together
How many strings are there using the letters of the word INTERMEDIATE, if all the vowels are together
Let b1, b2, b3, b4 be a 4-element permutation with bi ∈ {1, 2, 3, .......,100} for 1 ≤ i ≤ 4 and bi ≠ bj for i ≠ j, such that either b1, b2, b3 are consecutive integers or b2, b3, b4 are consecutive integers. Then the number of such permutations b1, b2, b3, b4 is equal to ______.
If m+nP2 = 90 and m–nP2 = 30, then (m, n) is given by ______.
