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In any Δ ABC, prove the following: b-ca=tan B2-tan C2tan B2+tan C2

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Question

In any Δ ABC, prove the following:

`("b" - "c")/"a" = (tan  "B"/2 - tan  "C"/2)/(tan  "B"/2 +tan  "C"/2)`

Sum
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Solution

By sine rule,

`"a"/"sin A" = "b"/"sin B" = "c"/"sin C"` = k

∴ a = k sin A, b = k sin B, c = k sin C

LHS = `("b" - "c")/"a"`

`= ("k sin B - k sin C")/"k sin A"`

`= ("sin B - sin C")/"sin A"`

`= ("sin B - sin C")/(sin {pi - ("B" + "C")})    ....[because "A + B + C" = pi]`

`= ("sin B - sin C")/(sin ("B + C"))`

`= (2 cos  (("B + C")/2). sin (("B" - "C")/2))/(2 sin  (("B + C")/2). cos (("B" + "C")/2))`

`= (sin  ("B - C")/2)/(sin   ("B" + "C")/2)`

`= sin("B"/2 - "C"/2)/sin ("B"/2 + "C"/2)`

`= (sin  "B"/2 cos  "C"/2 - cos  "B"/2 sin  "C"/2)/(sin  "B"/2 cos  "C"/2 + cos  "B"/2  sin  "C"/2)`

`= ((sin  "B"/2 cos  "C"/2)/(cos  "B"/2 cos  "C"/2) -  (cos  "B"/2 sin  "C"/2)/(cos  "B"/2 cos  "C"/2))/((sin  "B"/2 cos  "C"/2)/(cos  "B"/2 cos  "C"/2) + (cos  "B"/2 sin  "C"/2)/(cos  "B"/2 cos  "C"/2))`

`= ((sin  "B"/2)/(cos  "B"/2) - (sin  "C"/2)/(cos  "C"/2))/((sin  "B"/2)/(cos  "C"/2) + (sin  "C"/2)/(cos  "C"/2))`

`= (tan  "B"/2 - tan  "C"/2)/(tan  "B"/2 +  tan  "C"/2)`

= RHS.

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Chapter 3: Trigonometric Functions - Miscellaneous exercise 3 [Page 109]

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Balbharati Mathematics and Statistics 1 (Arts and Science) [English] Standard 12 Maharashtra State Board
Chapter 3 Trigonometric Functions
Miscellaneous exercise 3 | Q 11.7 | Page 109

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