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Question
If the solubility product of CuS is 6 × 10−16, calculate the maximum molarity of CuS in aqueous solution.
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Solution
Maximum molarity of CuS in an aqueous solution = Solubility of CuS in mol L−1
If S is the solubility of CuS in mol L−1, then,
\[\ce{CuS <=> Cu^{2+} + S^{2-}}\]
Ksp = [Cu2+][S2−]
= S × S
= S2
∴ S2 = 6 × 10−16
S = `sqrt (6 xx 10^-16)`
= 2.45 × 10−8 mol L−1
This is the maximum amount of CuS in 1 L of solution.
∴ The maximum molarity of the solution is 2.45 × 10−8 M.
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