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प्रश्न
If the solubility product of CuS is 6 × 10−16, calculate the maximum molarity of CuS in aqueous solution.
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उत्तर
Maximum molarity of CuS in an aqueous solution = Solubility of CuS in mol L−1
If s is the solubility of CuS in mol L−1, then
\[\ce{CuS <=> Cu^{2+} + S^{2-}}\]
Ksp = [Cu2+][S2−]
= s × s
= s2
∴ s2 = 6 × 10−16 or
s = `sqrt (6 xx 10^-16)`
s = 2.45 × 10−8 mol L−1
This is the maximum amount of CuS in 1 L of solution. Hence, the maximum molarity of the solution is 2.4 × 10−8 M.
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