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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

If the solubility product of CuS is 6 × 10^−16, calculate the maximum molarity of CuS in aqueous solution.

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प्रश्न

If the solubility product of CuS is 6 × 10−16, calculate the maximum molarity of CuS in aqueous solution.

संख्यात्मक
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उत्तर

Maximum molarity of CuS in an aqueous solution = Solubility of CuS in mol L−1

If S is the solubility of CuS in mol L−1, then,

\[\ce{CuS <=> Cu^{2+} + S^{2-}}\]

Ksp = [Cu2+][S2−]

= S × S

= S2

∴ S2 = 6 × 10−16

S = `sqrt (6 xx 10^-16)`

= 2.45 × 108 mol L1

This is the maximum amount of CuS in 1 L of solution.

∴ The maximum molarity of the solution is 2.45 × 10−8 M.

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अध्याय 1: Solutions - 'NCERT TEXT-BOOK' Exercises [पृष्ठ १२७]

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नूतन Chemistry [English] Class 12 ISC
अध्याय 1 Solutions
'NCERT TEXT-BOOK' Exercises | Q 2.27 | पृष्ठ १२७
एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
अध्याय 1 Solutions
Exercises | Q 1.27 | पृष्ठ २९

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