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If M and N Are the Order and Degree of the Differential Equation ( Y 2 ) 5 + 4 ( Y 2 ) 3 Y 3 + Y 3 = X 2 − 1 , Then

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Question

If m and n are the order and degree of the differential equation \[\left( y_2 \right)^5 + \frac{4 \left( y_2 \right)^3}{y_3} + y_3 = x^2 - 1\], then

Options

  • m = 3, n = 3

  • m = 3, n = 2

  • m = 3, n = 5

  • m = 3, n = 1

MCQ
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Solution

m = 3, n = 2
 
We have,
\[ \left( y_2 \right)^5 + \frac{4 \left( y_2 \right)^3}{y_3} + y_3 = x^2 - 1\]
\[ \Rightarrow y_3 \left( y_2 \right)^5 + 4 \left( y_2 \right)^3 + \left( y_3 \right)^2 = y_3 \left( x^2 - 1 \right)\]
\[\text{ The highest order derivative is }y_3\text{ and its highest exponent in this equation is 2.}\]
Therefore, order is 3 and degree is 2. 
Hence, m = 3, n = 2
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Chapter 21: Differential Equations - MCQ [Page 141]

APPEARS IN

R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 21 Differential Equations
MCQ | Q 26 | Page 141

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