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If f(x) = (4x + 3)/(6x – 4), x ≠ 2/3, show that fof (x) = x for all x ≠ 2/3. Also, find the inverse of f.

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Questions

If `f(x) = (4x + 3)/(6x - 4), x ≠ 2/3`, show that fof (x) = x for all `x ≠ 2/3`. Also, find the inverse of f.

If `f(x) = (4x + 3)/(6x - 4), x ≠ 2/3`, then show that (fof) (x) = x, for all `x ≠ 2/3`. Also, write inverse of f.

Sum
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Solution 1

f (x)  = `(4x + 3)/(6x - 4) ` 

`f (f (x)) = (4 f(x) + 3)/(6 f(x) - 4)`

`f(f(x))= (4 ((4x + 3)/(6x - 4))+3)/(6((4x + 3)/(6x - 4))-4)`

` fof (x) = (((16x + 12 + 18x - 12)/(6x -4)))/(((24x + 18 - 24 x + 16)/(6x - 4)))`

` fof (x) = (34x)/34`

fof (x) = x

For inversere y = `(4x + 3)/(6x - 4)`

6xy – 4y = 4x + 3

6 xy – 4x = 4y + 3 

x(6y – 4) = 4y + 3

`x = (4y + 3)/(6y - 4) ⇒ y = (4x + 3)/(6x - 4)`

`⇒ f^(-1) (x) = (4x + 3)/(6x - 4)`

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Solution 2

`f(x) = (4x +3)/(6x -4)      x ≠ 2/3`

`f "of"(x) = (4((4x +3)/(6x - 4))+ 3)/(6((4x +3)/(6x - 4)) - 4)`

= `(16x + 12 + 18x - 12)/(24x + 18 - 24x + 16)`

= `(34x)/(34) = x`

Therefore, fof (x) = x, for all `x ≠ 2/3`
⇒ fof = I
Hence, the given function f is invertible and the inverse of f is itself.

`y = (4x + 3)/(6x - 4)`

`6xy - 4y = 4x +3`

`6xy - 4y = 4y +3`

`x = (4y + 3)/(6y -4)`

∴ `f(x) = (4x +3)/(6x - 4)`

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Solution 3

fof (x) = f(f(x))

= `f((4x + 3)/(6x - 4))`

= `(4((4x  +  3)/(6x  -  4)) + 3)/(6((4x  +  3)/(6x  -  4)) - 4)`

= `(16x + 12 + 18x - 12)/(24x + 18 - 24x + 16)`

= `(34x)/34`

= x

Now, suppose `y = (4x + 3)/(6x - 4)`

⇒ 6xy – 4y = 4x + 3

⇒ 6xy – 4x = 3 + 4y

⇒ x(6y – 4) = 3 + 4y

⇒ `x = (3 + 4y)/(6y - 4)`

Therefore, `f^-1 = (3 + 4y)/(6y - 4)`

So here inverse of f is equal to function f.

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Notes

Students should refer to the answer according to their questions.

  Is there an error in this question or solution?
2018-2019 (March) 65/3/3

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