Advertisements
Advertisements
Question
If A(x, 2), B(−3, −4) and C(7, −5) are collinear, then the value of x is
Options
−63
63
60
−60
Advertisements
Solution
The given points A(x, 2), B(−3, −4) and C(7, −5) are collinear.
\[\therefore ar\left( ∆ ABC \right) = 0\]
\[ \Rightarrow \frac{1}{2}\left| x_1 \left( y_2 - y_3 \right) + x_2 \left( y_3 - y_1 \right) + x_3 \left( y_1 - y_2 \right) \right| = 0\]
\[ \Rightarrow x_1 \left( y_2 - y_3 \right) + x_2 \left( y_3 - y_1 \right) + x_3 \left( y_1 - y_2 \right) = 0\]
\[\Rightarrow x\left[ - 4 - \left( - 5 \right) \right] + \left( - 3 \right)\left( - 5 - 2 \right) + 7\left[ 2 - \left( - 4 \right) \right] = 0\]
\[ \Rightarrow x + 21 + 42 = 0\]
\[ \Rightarrow x + 63 = 0\]
\[ \Rightarrow x = - 63\]
Thus, the value of x is −63.
APPEARS IN
RELATED QUESTIONS
Find the centre of the circle passing through (5, -8), (2, -9) and (2, 1).
Prove that the points (0, 0), (5, 5) and (-5, 5) are the vertices of a right isosceles triangle.
Determine the ratio in which the straight line x - y - 2 = 0 divides the line segment
joining (3, -1) and (8, 9).
If the point P (2,2) is equidistant from the points A ( -2,K ) and B( -2K , -3) , find k. Also, find the length of AP.
If the point ( x,y ) is equidistant form the points ( a+b,b-a ) and (a-b ,a+b ) , prove that bx = ay
Show that the points A(6,1), B(8,2), C(9,4) and D(7,3) are the vertices of a rhombus. Find its area.
The midpoint of the line segment joining A (2a, 4) and B (-2, 3b) is C (1, 2a+1). Find the values of a and b.
The line segment joining A( 2,9) and B(6,3) is a diameter of a circle with center C. Find the coordinates of C
If the point `P (1/2,y)` lies on the line segment joining the points A(3, -5) and B(-7, 9) then find the ratio in which P divides AB. Also, find the value of y.
Find the area of a quadrilateral ABCD whose vertices area A(3, -1), B(9, -5) C(14, 0) and D(9, 19).
Find the area of quadrilateral ABCD whose vertices are A(-5, 7), B(-4, -5) C(-1,-6) and D(4,5)
Find the ratio in which the point (−3, k) divides the line-segment joining the points (−5, −4) and (−2, 3). Also find the value of k ?
A point whose abscissa and ordinate are 2 and −5 respectively, lies in
If the distance between the points (4, p) and (1, 0) is 5, then p =
If (x , 2), (−3, −4) and (7, −5) are collinear, then x =
The line segment joining points (−3, −4), and (1, −2) is divided by y-axis in the ratio.
If (−2, 1) is the centroid of the triangle having its vertices at (x , 0) (5, −2), (−8, y), then x, y satisfy the relation
In Fig. 14.46, the area of ΔABC (in square units) is

The distance of the point (–4, 3) from y-axis is ______.
The distance of the point (3, 5) from x-axis (in units) is ______.
