मराठी

If A(X, 2), B(−3, −4) and C(7, −5) Are Collinear, Then the Value of X is - Mathematics

Advertisements
Advertisements

प्रश्न

If A(x, 2), B(−3, −4) and C(7, −5) are collinear, then the value of x is

पर्याय

  •  −63 

  • 63         

  • 60    

  •  −60       

MCQ
Advertisements

उत्तर

The given points A(x, 2), B(−3, −4) and C(7, −5) are collinear.

\[\therefore ar\left( ∆ ABC \right) = 0\]
\[ \Rightarrow \frac{1}{2}\left| x_1 \left( y_2 - y_3 \right) + x_2 \left( y_3 - y_1 \right) + x_3 \left( y_1 - y_2 \right) \right| = 0\]
\[ \Rightarrow x_1 \left( y_2 - y_3 \right) + x_2 \left( y_3 - y_1 \right) + x_3 \left( y_1 - y_2 \right) = 0\]

\[\Rightarrow x\left[ - 4 - \left( - 5 \right) \right] + \left( - 3 \right)\left( - 5 - 2 \right) + 7\left[ 2 - \left( - 4 \right) \right] = 0\]

\[ \Rightarrow x + 21 + 42 = 0\]

\[ \Rightarrow x + 63 = 0\]

\[ \Rightarrow x = - 63\]

Thus, the value of x is −63.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 6: Co-Ordinate Geometry - Exercise 6.7 [पृष्ठ ६६]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 10
पाठ 6 Co-Ordinate Geometry
Exercise 6.7 | Q 47 | पृष्ठ ६६

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

The coordinates of the point P are (−3, 2). Find the coordinates of the point Q which lies on the line joining P and origin such that OP = OQ.


Find the value of x such that PQ = QR where the coordinates of P, Q and R are (6, -1), (1, 3) and (x, 8) respectively.


Find the points of trisection of the line segment joining the points:

5, −6 and (−7, 5),


The points A(2, 0), B(9, 1) C(11, 6) and D(4, 4) are the vertices of a quadrilateral ABCD. Determine whether ABCD is a rhombus or not.


Find the points on the y-axis which is equidistant form the points A(6,5)  and B(- 4,3) 


Show that the following points are the vertices of a square:

A (0,-2), B(3,1), C(0,4) and D(-3,1)


Show that the points A(2,1), B(5,2), C(6,4) and D(3,3) are the angular points of a parallelogram. Is this figure a rectangle?


Find the area of quadrilateral ABCD whose vertices are A(-3, -1), B(-2,-4) C(4,-1) and D(3,4)


Point P(x, 4) lies on the line segment joining the points A(−5, 8) and B(4, −10). Find the ratio in which point P divides the line segment AB. Also find the value of x.


The perpendicular distance of the P (4,3)  from y-axis is


Find the area of a parallelogram ABCD if three of its vertices are A(2, 4), B(2 + \[\sqrt{3}\] , 5) and C(2, 6).                 

 


\[A\left( 6, 1 \right) , B(8, 2) \text{ and }  C(9, 4)\] are three vertices of a parallelogram ABCD . If E is the mid-point  of DC , find the area of  \[∆\] ADE.

 

If  \[D\left( - \frac{1}{5}, \frac{5}{2} \right), E(7, 3) \text{ and }  F\left( \frac{7}{2}, \frac{7}{2} \right)\]  are the mid-points of sides of  \[∆ ABC\] ,  find the area of  \[∆ ABC\] .


What is the area of the triangle formed by the points O (0, 0), A (6, 0) and B (0, 4)?

 

If A (1, 2) B (4, 3) and C (6, 6) are the three vertices of a parallelogram ABCD, find the coordinates of fourth vertex D.

 

If points (t, 2t), (−2, 6) and (3, 1) are collinear, then t =


If the sum of X-coordinates of the vertices of a triangle is 12 and the sum of Y-coordinates is 9, then the coordinates of centroid are ______


What are the coordinates of origin?


Ordinate of all points on the x-axis is ______.


The distance of the point (3, 5) from x-axis (in units) is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×