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Question
How is the following conversion carried out?
\[\ce{Propene -> Propan-2-ol}\]
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Solution
If propene is allowed to react with water in the presence of an acid as a catalyst, then propan-2-ol is obtained.
\[\begin{array}{cc}
\ce{\underset{Propene}{CH3 - CH = CH2}->[H2O/H+][\Delta]CH3 - CH - CH3}\\
\phantom{........................................}|\\
\phantom{...........................................}\ce{\underset{Propan-2-ol}{OH}}\\
\end{array}\]
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\ce{Cl}\phantom{.........................}\\
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