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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

How is the following conversion carried out? Propene -> Propan-2-ol

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प्रश्न

How is the following conversion carried out?

\[\ce{Propene -> Propan-2-ol}\]

रासायनिक समीकरण/संरचनाएँ
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उत्तर

If propene is allowed to react with water in the presence of an acid as a catalyst, then propan-2-ol is obtained.

\[\begin{array}{cc}
\ce{\underset{Propene}{CH3 - CH = CH2}->[H2O/H+][\Delta]CH3 - CH - CH3}\\
\phantom{........................................}|\\
\phantom{...........................................}\ce{\underset{Propan-2-ol}{OH}}\\
\end{array}\]

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अध्याय 7: Alcohols, Phenols and Ethers - Exercises [पृष्ठ २२३]

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एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
अध्याय 7 Alcohols, Phenols and Ethers
Exercises | Q 7.20 (i) | पृष्ठ २२३

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\end{array}\]


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