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प्रश्न
How is the following conversion carried out?
\[\ce{Ethyl magnesium chloride -> Propan-1-ol}\]
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उत्तर
When ethyl magnesium chloride is treated with methanal, an adduct produces propan-1-ol on hydrolysis.
\[\begin{array}{cc}
\ce{H}\phantom{.................................}\\
\backslash\phantom{..............................}\\
\ce{C = O + C2H5 - MgCl ->}\phantom{.}\\
/\phantom{..............................}\\
\ce{H}\phantom{.................................}
\end{array}\]\[\begin{bmatrix}
\ce{CH2 - \overset{-}{O}\overset{+}{M}gCl}\\
|\phantom{.............}\\
\ce{C2H5}\phantom{.........}\\
\ce{Adduct}
\end{bmatrix}\]\[\begin{array}{cc}
\ce{->[H2O]}
\ce{\underset{Propan-1-ol}{C3H7 - OH} + Mg(OH)Cl}
\end{array}\]
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\[\begin{array}{cc}
\ce{Cl}\phantom{.........................}\\
|\phantom{..........................}\\
\ce{CH3 - CH - CH3 ->[(i) Alc. KOH][(ii) HBr/peroxide (iii) aq. KOH]}
\end{array}\]
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\[\ce{Methyl magnesium bromide ->2-Methylpropan-2-ol}\]
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\[\ce{Methyl magnesium bromide -> 2-Methylpropan-2-ol}\]
