Advertisements
Advertisements
Question
How can the presence of ultraviolet radiation be detected?
Advertisements
Solution
In the presence of ultra-violet radiation, the silver chloride solution becomes dark brown or black.
RELATED QUESTIONS
The path of a ray of light passing through a glass prism is shown below:

In this diagram, the angle of prism, angle of incidence, angle of emergence and angle of deviation, respectively, have been represented by:
(A) O, Y, Z and N,
(B) P, Y, M and Z,
(C) O, X, M and Z,
(D) P, X, Z and N.
Which of the following coloured light has the least speed in glass prism?
(a) violet
(b) yellow
(c) red
(d) green
In figure AO is the ray of white light falling on a prism PQR. Complete the diagram till the light emerges out from the prism and falls on the screen.

The frequency range of visible light is from 3.75 × 1014 Hz to 7.5 × 1014 Hz. Calculate its wavelength range. Take speed of light = 3 × 108 m/s.
Suggest one way, in each case, by which we can detect the presence of Infrared radiations.
In the figure, a beam of light consisting of three colours blue, red, and yellow is incident on a prism and on a rectangular glass block respectively. Complete the diagram by drawings of the refracted and emergent rays.

The splitting of white light in to seven colors is called ______.
What is dispersion? Explain in detail.
A prism of refractive index `sqrt2` and refracting angle A produces minimum deviation δm of a ray on one face at an angle of incidence 45°, The values of A and δm are, respectively ______.
In the following diagram showing dispersion of white light by a glass prism, the colours 'P' and 'Q’ respectively are:

