Advertisements
Advertisements
Question
How are ethylamine and ethyl methyl amine distinguished by using nitrous acid?
Advertisements
Solution
An action of nitrous acid on ethylamine
An action of nitrous acid on ethylmethylamine
When the nitrous acid reacts with primary amine like C2H5NH2 it gives ethanol while when nitrous acid reactions with secondary amine like ethylmethylamine it gives yellow oily N-nitrosamine.
APPEARS IN
RELATED QUESTIONS
Convert aniline into 1, 3, 5-tribromobenzene.
Write the IUPAC name of the following compound and classify it as primary, secondary and tertiary amine.
(CH3)2CHNH2
Write the IUPAC name of the following compound and classify it as primary, secondary and tertiary amine.
C6H5NHCH3
Write the IUPAC name of the following compound and classify it as primary, secondary and tertiary amine.
(CH3CH2)2NCH3
Give one chemical test to distinguish between the following pair of compounds.
Methylamine and dimethylamine
Give one chemical test to distinguish between the following pair of compounds.
Secondary and tertiary amines
Give one chemical test to distinguish between the following pair of compounds.
Aniline and benzylamine
Account for the following:
pKb of aniline is more than that of methylamine.
Account for the following:
Ethylamine is soluble in water, whereas aniline is not.
Account for the following:
Methylamine in water reacts with ferric chloride to precipitate hydrated ferric oxide.
How will you convert ethanamine into methanamine?
How will you convert methanamine into ethanamine?
Accomplish the following conversion:
Chlorobenzene to p-chloroaniline
Accomplish the following conversion:
Aniline to benzyl alcohol
Complete the following reaction:
\[\ce{C6H5N2Cl + C2H5OH ->}\]
Complete the following reaction:
\[\ce{C6H5NH2 + Br2 (aq) ->}\]
Complete the following reaction:
\[\ce{C6H5NH2 + (CH3CO)2O ->}\]
Give reasons Although –NH2 is o/p directing group, yet aniline on nitration gives a significant amount of m-nitroaniline
Write the IUPAC name of the given compound :
The following amine is called as:
Do the following conversions in not more than two steps:
\[\begin{array}{cc}
\ce{CH3CN to CH3 - C - CH3}\\
\phantom{...........}||\\
\phantom{...........}\ce{O}
\end{array}\]
Do the following conversions in not more than two steps:
