English
Maharashtra State BoardSSC (English Medium) 10th Standard

From the Figure Find the Value of Sinθ. - Geometry Mathematics 2

Advertisements
Advertisements

Question

From the figure find the value of sinθ.

Sum
Advertisements

Solution

`sinθ = ("AB")/("AC")`

`sinθ = 3/5`

shaalaa.com
  Is there an error in this question or solution?
2018-2019 (March) Balbharati Model Question Paper Set 1

RELATED QUESTIONS

 Evaluate sin25° cos65° + cos25° sin65°


Prove that (cosec A – sin A)(sec A – cos A) sec2 A = tan A.


Prove the following trigonometric identities.

`(1 + sin θ)/cos θ+ cos θ/(1 + sin θ) = 2 sec θ`


Prove the following trigonometric identities.

`(1 - tan^2 A)/(cot^2 A -1) = tan^2 A`


Prove the following trigonometric identities.

`(tan A + tan B)/(cot A + cot B) = tan A tan B`


Prove the following identities:

`1/(1 - sinA) + 1/(1 + sinA) = 2sec^2A`


Prove the following identities:

(1 + tan A + sec A) (1 + cot A – cosec A) = 2


`sin theta/((cot theta + cosec  theta)) - sin theta /( (cot theta - cosec  theta)) =2`


Find the value of `(cos 38° cosec 52°)/(tan 18° tan 35° tan 60° tan 72° tan 55°)`


If sec θ + tan θ = x, then sec θ =


Prove the following identity :

(secA - cosA)(secA + cosA) = `sin^2A + tan^2A`


Prove the following identity :

`(cosecA - sinA)(secA - cosA)(tanA + cotA) = 1`


Prove that (cosec A - sin A)( sec A - cos A) sec2 A = tan A.


Prove that `(cot "A" + "cosec A" - 1)/(cot "A" - "cosec A" + 1) = (1 + cos "A")/sin "A"`


Proved that cosec2(90° - θ) - tan2 θ = cos2(90° - θ)  +  cos2 θ.


Prove that: `1/(cosec"A" - cot"A") - 1/sin"A" = 1/sin"A" - 1/(cosec"A" + cot"A")`


Prove the following identities.

`(cot theta - cos theta)/(cot theta + cos theta) = ("cosec"  theta - 1)/("cosec"  theta + 1)`


To prove cot θ + tan θ = cosec θ × sec θ, complete the activity given below.

Activity:

L.H.S = `square`

= `square/sintheta + sintheta/costheta`

= `(cos^2theta + sin^2theta)/square`

= `1/(sintheta*costheta)`     ......`[cos^2theta + sin^2theta = square]`

= `1/sintheta xx 1/square`

= `square`

= R.H.S


If 5 tan β = 4, then `(5  sin β - 2 cos β)/(5 sin β + 2 cos β)` = ______.


Let x1, x2, x3 be the solutions of `tan^-1((2x + 1)/(x + 1)) + tan^-1((2x - 1)/(x - 1))` = 2tan–1(x + 1) where x1 < x2 < x3 then 2x1 + x2 + x32 is equal to ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×