Advertisements
Advertisements
Question

From the figure find the value of sinθ.
Advertisements
Solution
`sinθ = ("AB")/("AC")`
`sinθ = 3/5`
APPEARS IN
RELATED QUESTIONS
Prove the following trigonometric identities.
`(sec A - tan A)/(sec A + tan A) = (cos^2 A)/(1 + sin A)^2`
`1/((1+tan^2 theta)) + 1/((1+ tan^2 theta))`
`(1+ cos theta)(1- costheta )(1+cos^2 theta)=1`
Find the value of ` ( sin 50°)/(cos 40°)+ (cosec 40°)/(sec 50°) - 4 cos 50° cosec 40 °`
Prove that:
`"tanθ"/("secθ" – 1) = (tanθ + secθ + 1)/(tanθ + secθ - 1)`
cos4 A − sin4 A is equal to ______.
Prove the following identity :
`sinθ(1 + tanθ) + cosθ(1 +cotθ) = secθ + cosecθ`
Prove the following identity :
`sin^2Acos^2B - cos^2Asin^2B = sin^2A - sin^2B`
If A + B = 90°, show that sec2 A + sec2 B = sec2 A. sec2 B.
Prove the following identities:
`(1 - tan^2 θ)/(cot^2 θ - 1) = tan^2 θ`.
Prove that: `(sin θ - 2sin^3 θ)/(2 cos^3 θ - cos θ) = tan θ`.
If 5x = sec θ and `5/x` = tan θ, then `x^2 - 1/x^2` is equal to
a cot θ + b cosec θ = p and b cot θ + a cosec θ = q then p2 – q2 is equal to
Prove that `cot^2 "A" [(sec "A" - 1)/(1 + sin "A")] + sec^2 "A" [(sin"A" - 1)/(1 + sec"A")]` = 0
Prove that `(cos(90^circ - A))/(sin A) = (sin(90^circ - A))/(cos A)`.
Prove that `(tan(90 - θ) + cot(90 - θ))/("cosec" θ) = sec θ`.
Prove that sin4A – cos4A = 1 – 2 cos2A.
If 2sin2β − cos2β = 2, then β is ______.
If tan α + cot α = 2, then tan20α + cot20α = ______.
tan θ × `sqrt(1 - sin^2 θ)` is equal to:
