English

Four Point Charges Q, Q, Q and Q Are Placed at the Corners of a Square of Side 'A' as Shown in the Figure.

Advertisements
Advertisements

Question

Four point charges Q, q, Q and q are placed at the corners of a square of side 'a' as shown in the figure.

Find the

1) resultant electric force on a charge Q, and

2) potential energy of this system.

Advertisements

Solution

1) `F_"net" = "KQ"^2/(2a^2) + (sqrt2KQq)/a^2`

2) Potential energy of the system = `(4KQq)/a + "KQ"^2/(sqrt2a) + (Kq^2)/(sqrt2a)`

shaalaa.com
  Is there an error in this question or solution?
2017-2018 (March) Delhi Set 1

RELATED QUESTIONS

A cube of side b has a charge q at each of its vertices. Determine the potential and electric field due to this charge array at the centre of the cube.


If one of the two electrons of a Hmolecule is removed, we get a hydrogen molecular ion `"H"_2^+`. In the ground state of an `"H"_2^+`, the two protons are separated by roughly 1.5 Å, and the electron is roughly 1 Å from each proton. Determine the potential energy of the system. Specify your choice of zero potential energy.


A point charge Q is placed at point 'O' as shown in the figure. Is the potential at point A, i.e. VA, greater, smaller or equal to potential, VB, at point B, when Q is (i) positive, and (ii) negative charge?


A point charge Q is placed at point O as shown in the figure. The potential difference VA – VB positive. Is the charge Q negative or positive?


Figure shows the field lines due to a positive point charge. Give the sign of potential energy difference of a small negative charge between the points Q and P.


1 volt is equivalent to ______.


In the circuit shown in figure initially, key K1 is closed and key K2 is open. Then K1 is opened and K2 is closed (order is important). [Take Q1′ and Q2′ as charges on C1 and C2 and V1 and V2 as voltage respectively.]

Then

  1. charge on C1 gets redistributed such that V1 = V2
  2. charge on C1 gets redistributed such that Q1′ = Q2
  3. charge on C1 gets redistributed such that C1V1 + C2V2 = C1E
  4. charge on C1 gets redistributed such that Q1′ + Q2′ = Q

Calculate potential energy of a point charge – q placed along the axis due to a charge +Q uniformly distributed along a ring of radius R. Sketch P.E. as a function of axial distance z from the centre of the ring. Looking at graph, can you see what would happen if – q is displaced slightly from the centre of the ring (along the axis)?


  1. In a quark model of elementary particles, a neutron is made of one up quarks [charge (2/3) e] and two down quarks [charges –(1/3) e]. Assume that they have a triangle configuration with side length of the order of 10–15 m. Calculate electrostatic potential energy of neutron and compare it with its mass 939 MeV.
  2. Repeat above exercise for a proton which is made of two up and one down quark.

  • Assertion (A): Work done in moving a charge around a closed path, in an electric field is always zero.
  • Reason (R): Electrostatic force is a conservative force.

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×