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For the Following Differential Equation, Find the General Solution:- D Y D X = √ 4 − Y 2 , − 2 < Y < 2

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Question

For the following differential equation, find the general solution:- \[\frac{dy}{dx} = \sqrt{4 - y^2}, - 2 < y < 2\]

Sum
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Solution

We have, 

\[\frac{dy}{dx} = \sqrt{4 - y^2}\]

\[ \Rightarrow \frac{1}{\sqrt{4 - y^2}}dy = dx\]

Integrating both sides, we get

\[\int\frac{1}{\sqrt{4 - y^2}}dy = \int dx\]

\[ \Rightarrow \sin^{- 1} \frac{y}{2} = x + C\]

\[ \Rightarrow \frac{y}{2} = \sin \left( x + C \right)\]

\[ \Rightarrow y = 2\sin \left( x + C \right)\]

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Chapter 21: Differential Equations - Revision Exercise [Page 146]

APPEARS IN

R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 21 Differential Equations
Revision Exercise | Q 64.2 | Page 146

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