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Find: ∫x+1(x2+1)xdx

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Question

Find: `int (x + 1)/((x^2 + 1)x) dx`

Sum
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Solution

Let `(x + 1)/((x^2 + 1)x) = (Ax + B)/(x^2 + 1) + C/x = ((Ax + B)x + C(x^2 + 1))/((x^2 + 1)x)`

⇒ `x + 1 = (Ax + B)x + C(x^2 + 1)`  .....(An identity)

Equating the coefficients, we get

B = 1, C = 1, A + C = 0

Hence, A = –1, B = 1, C = 1

The given integral = `int (-x + 1)/(x^2 + 1) dx + int 1/x dx`

= `(-1)/2 int (2x - 2)/(x^2 + 1) dx + int 1/x dx`

= `(-1)/2 int (2x)/(x^2 + 1) dx + int 1/(x^2 + 1) dx + int 1/x dx`

= `(-1)/2 log(x^2 + 1) + tan^-1x + log |x| + c`

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2021-2022 (March) Term 2 Sample

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