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Question
Find the slope of the tangent to the following curves at the respective given points.
y = x4 + 2x2 – x at x = 1
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Solution
y = x4 + 2x2 – x
Differentiating w.r.t. ‘x’
`"d"y)/("d"x = 4x3 + 4x – 1
Slope of the tangent `(("d"y)/("d"x))_((x = 1))`
= 4(1)³ + 4(1) – 1
= 4 + 4 – 1
= 7
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