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Tamil Nadu Board of Secondary EducationHSC Science Class 12

Find the tangent and normal to the following curves at the given points on the curve y = x4 + 2ex at (0, 2)

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Question

Find the tangent and normal to the following curves at the given points on the curve

y = x4 + 2ex at (0, 2)

Sum
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Solution

y = x4 + 2ex at (0, 2)

Differentiating w.r.t. ‘x’

`("d"y)/("d"x)` = 4x3 + 2ex

Slope of the tangent ‘m’

`(("d"y)/("d"x))_(((0, 2))` = 4(0)3 + 2e0 = 2

Slope of the Normal `- 1/"m" = - 1/2`

Equation of tangent is

y – y1 = m(x – x1)

⇒ y – 2 = 2(x – 0)

⇒ y – 2 = 2x

⇒ 2x – y + 2 = 0

Equation of Normal is

y – y1 = `- 1/"m"` (x – x1)

y – 2 = `- 1/2` (x – 0)

2y – 4 = – x

x + 2y – 4 = 0

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Chapter 7: Applications of Differential Calculus - Exercise 7.2 [Page 15]

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Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 12 TN Board
Chapter 7 Applications of Differential Calculus
Exercise 7.2 | Q 5. (ii) | Page 15

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