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Tamil Nadu Board of Secondary EducationHSC Science Class 12

Find the equations of the tangents to the curve y = 1 + x3 for which the tangent is orthogonal with the line x + 12y = 12 - Mathematics

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Question

Find the equations of the tangents to the curve y = 1 + x3 for which the tangent is orthogonal with the line x + 12y = 12

Sum
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Solution

Curve y = 1 + x3 

Differentiating w.r.t ‘x’

Slope of the tangent ‘m’ = `("d"y)/("d"x)` = 3x2

Given line is x + 12y = 12

Slope of the line is `- 1/12`

Since the tangent is orthogonal with the line, the slope of the tangent is 12.

∴ `("d"y)/("d"x)` = 12

i.e 3x2 = 12

x2 = 4

x = ± 2

When x = 2

y = 1 + 8

= 9

⇒ point is (2, 9)

When x = – 2

y = 1 – 8

= – 7

⇒ point is (– 2, – 7)

Equation of tangent with slope 12 and at the j point (2, 9) is

y – 9 = 12(x – 2)

y – 9 = 12x – 24

12x – y – 15 = 0

Equation of tangent with slope 12 and at the point (– 2, – 7) is

y + 7 = 12(x + 2)

y + 7 = 12x + 24

12x – y + 17 = 0

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Chapter 7: Applications of Differential Calculus - Exercise 7.2 [Page 15]

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Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 12 TN Board
Chapter 7 Applications of Differential Calculus
Exercise 7.2 | Q 6 | Page 15

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