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Find the pressure 200 m below the surface of the ocean if pressure on the free surface of liquid is one atmosphere. (Density of seawater = 1060 kg/m3)

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Question

Find the pressure 200m below the surface of the ocean if pressure on the free surface of liquid is one atmosphere. (Density of seawater = 1060 kg/m3)

Sum
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Solution

Given:

h = 200m,

ρ = 1060 kg/m³,

P0 = 1.013 × 105

Pa, g = 9.8 m/s²

To find:

Presssure 200m below the surface

Solution:

Absolute pressure, P = P0 + hρg

= (1.013 x 105) + (200 x 1060) x (9.8)

= (1.013 × 105) + (20.776 × 105)

= 21.789 × 105

= 2.1789 MPa

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Chapter 2: Mechanical Properties of Fluids - Exercises [Page 55]

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Balbharati Physics [English] Standard 12 Maharashtra State Board
Chapter 2 Mechanical Properties of Fluids
Exercises | Q 10 | Page 55

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