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Question
In a hydraulic lift, the input piston had surface area 30 cm2 and the output piston has surface area of 1500 cm2. If a force of 25 N is applied to the input piston, calculate weight/force on output piston.
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Solution
Given:
A1 = 30 cm2 = 3 × 10−3 m2
A2 = 1500 cm2 = 0.15 m2,
F1 = 25 N
To find:
Weight on output piston.
Solution:
Using Pascal's law,
`"F"_1/"A"_1="F"_2/"A"_2`
∴ The force on the output piston,
F2 = `("F"_1 "A"_2)/"A"_1=(25 xx 0.15)/(3xx10^-3)`
= 25 × 50
= 1250 N
∴ The weight/force on the output piston is 1250 N.
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