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In a hydraulic lift, the input piston had surface area 30 cm2 and the output piston has surface area of 1500 cm2. If a force of 25 N is applied to the input piston, calculate weight/force on output

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प्रश्न

In a hydraulic lift, the input piston had surface area 30 cm2 and the output piston has surface area of 1500 cm2. If a force of 25 N is applied to the input piston, calculate weight/force on output piston.

संख्यात्मक
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उत्तर

Given:

A1 = 30 cm2 = 3 × 10−3 m2

A2 = 1500 cm2 = 0.15 m2,

F1 = 25 N

To find:

Weight on output piston.

Solution:

Using Pascal's law,

`"F"_1/"A"_1="F"_2/"A"_2`

∴ The force on the output piston,

F2 = `("F"_1 "A"_2)/"A"_1=(25 xx 0.15)/(3xx10^-3)`

= 25 × 50

= 1250 N

∴ The weight/force on the output piston is 1250 N.

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अध्याय 2: Mechanical Properties of Fluids - Exercises [पृष्ठ ५५]

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बालभारती Physics [English] Standard 12 Maharashtra State Board
अध्याय 2 Mechanical Properties of Fluids
Exercises | Q 11 | पृष्ठ ५५

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