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Find the number of integers greater than 7000 that can be formed with the digits 3, 5, 7, 8 and 9 where no digits are repeated. - Mathematics

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Question

Find the number of integers greater than 7000 that can be formed with the digits 3, 5, 7, 8 and 9 where no digits are repeated.

Sum
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Solution

Given that all the 5 digit numbers are greater than 7000.

So, the ways of forming 5-digit numbers = 5 × 4 × 3 × 2 × 1 = 120

Now all the four-digit number greater than 7000 can be formed as follows.

Thousand place can be filled with 3 ways

Hundred place can be filled with 4 ways

Tenths place can be filled with 3 ways

Units place can be filled with 2 ways

So, the total number of 4-digits numbers = 3 × 4 × 3 × 2 = 72  

∴ Total number of integers = 120 + 72 = 192

Hence, the required number of integers = 192

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Chapter 7: Permutations and Combinations - Exercise [Page 123]

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NCERT Exemplar Mathematics [English] Class 11
Chapter 7 Permutations and Combinations
Exercise | Q 16 | Page 123

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