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How many 3-digit even numbers can be formed from the digits 1, 2, 3, 4, 5, 6 if the digits can be repeated?

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Question

How many 3-digit even numbers can be formed from the digits 1, 2, 3, 4, 5, 6 if the digits can be repeated?

Sum
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Solution

There will be as many ways as there are ways of filling 3 vacant places in succession with the given six digits. In this case, the units place can be filled by 2 or 4 or 6 only, i.e., the units place can be filled in 3 ways. The tens place can be filled by any of the 6 digits in 6 different ways and the hundreds place can be filled by any of the 6 digits in 6 different ways, as the digits can be repeated.

Therefore, by the multiplication principle, the required number of three digit even numbers is 3 × 6 × 6 = 108.

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Chapter 6: Permutations and Combinations - EXERCISE 6.1 [Page 104]

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NCERT Mathematics [English] Class 11
Chapter 6 Permutations and Combinations
EXERCISE 6.1 | Q 2. | Page 104

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