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Question
How many three-digit numbers, which are divisible by 5, can be formed using the digits 0, 1, 2, 3, 4, 5 if repetition of digits are allowed?
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Solution
The digits are 0 1 2 3 4 5
To get a number divisible by 5 we should have the unit place as 5 or 0
So the unit place (using 0 or 5) can be filled in 2 ways.
The 10’s place can be filled (Using 0, 1, 2, 3, 4, 5) in 6 ways
And the 100’s place (Using 1, 2, 3, 4, 5) can be filled in 5 ways
So the number of 3 digit numbers ÷ by 5 (with repetition) = 2 × 6 × 5 = 60
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