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How many three-digit numbers, which are divisible by 5, can be formed using the digits 0, 1, 2, 3, 4, 5 if repetition of digits are allowed?

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प्रश्न

How many three-digit numbers, which are divisible by 5, can be formed using the digits 0, 1, 2, 3, 4, 5 if repetition of digits are allowed?

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उत्तर

The digits are 0 1 2 3 4 5

To get a number divisible by 5 we should have the unit place as 5 or 0

So the unit place (using 0 or 5) can be filled in 2 ways.

The 10’s place can be filled (Using 0, 1, 2, 3, 4, 5) in 6 ways

And the 100’s place (Using 1, 2, 3, 4, 5) can be filled in 5 ways

So the number of 3 digit numbers ÷ by 5 (with repetition) = 2 × 6 × 5 = 60

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 4: Combinatorics and Mathematical Induction - Exercise 4.1 [पृष्ठ १६६]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
पाठ 4 Combinatorics and Mathematical Induction
Exercise 4.1 | Q 9. (ii) | पृष्ठ १६६

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