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Count the numbers between 999 and 10000 subject to the condition that there are no digit is repeated

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प्रश्न

Count the numbers between 999 and 10000 subject to the condition that there are no digit is repeated

बेरीज
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उत्तर

Since 0 is given as a digit

We have to start filling 1000’s place.

Now 1000’s place can be filled in 9 ways (excluding 0)

Then the 100’s place can be filled in 9 ways (excluding one digit and including 0)

10’s place can be filled in (9 – 1)8 ways and unit place can be filled in (8 – 1)7 ways

So the number of 4 digit numbers are 9 × 9 × 8 × 7 = 4536 ways

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 4: Combinatorics and Mathematical Induction - Exercise 4.1 [पृष्ठ १६६]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
पाठ 4 Combinatorics and Mathematical Induction
Exercise 4.1 | Q 8. (ii) | पृष्ठ १६६

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