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How many five-digit numbers formed using the digit 0, 1, 2, 3, 4, 5 are divisible by 5 if digits are not repeated?

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Question

How many five-digit numbers formed using the digit 0, 1, 2, 3, 4, 5 are divisible by 5 if digits are not repeated?

Sum
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Solution

For a number to be divisible by 5,

Unit’s place digit should be 0 or 5.

Case I: when unit’s place is 0

Unit’s place digit can be selected in 1 way.

10’s place digit can be selected in 5 ways.

100’s place digit can be selected in 4 ways.

1000’s place digit can be selected in 3 ways.

10000’s place digit can be selected in 2 ways.

∴ total number of numbers = 1 × 5 × 4 × 3 × 2 = 120

Case II: when unit’s place is 5

Unit’s place digit can be selected in 1 way

10000’s place should be a non-zero number

∴ It can be selected in 4 ways

1000’s place digit can be selected in 4 ways.

100’s place digit can be selected in 3 ways.

10’s place digit can be selected in 2 ways.

∴ total number of numbers = 1 × 4 × 4 × 3 × 2 = 96

∴ Required number = 120 + 96 = 216

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Chapter 3: Permutations and Combination - Exercise 3.1 [Page 48]

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