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Question
How many three-digit odd numbers can be formed by using the digits 0, 1, 2, 3, 4, 5? if the repetition of digits is allowed
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Solution
The given digits are 0, 1, 2, 3, 4, 5
To find the possible 3-digit odd numbers.
Repetition of digits is allowed:
| Hundred's | Ten's | Unit |
The unit place can be filled in 3 ways.
We are given 6 digits.
So 10’s place can be filled in 6 ways and the 100’s place can be filled in (6 – 1)(excluding zero)5 ways
So the Number of 3 digit numbers = 3 × 6 × 5 = 90
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