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Find the maximum and minimum of the following functions : f(x) = x log x

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Question

Find the maximum and minimum of the following functions : f(x) = x log x

Sum
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Solution

f(x) = x log x

∴ f'(x) = `d/dx (x log x)`

= `x.d/dx (log x) + logx.d/dx(x)`

= `x xx (1)/x + (log x) xx 1`
= 1 + log x
and
f"(x) = `d/dx(1 + log x)`

= `0 + (1)/x = (1)/x`

Now, f'(x) = 0, if 1 + log x = 0
i.e. if log x = – 1 = – log e

i.e. if log x = `log(e^-1) = log(1)/e`

i.e. if x = `(1)/e`

When `x = (1)e, f"(x) = (1)/((1/e)` = e > 0

∴ by the second derivative test, f is minimum at x = `(1)/e`.

Minimum value of f at x = `(1)/e`

 = `(1)/elog(1/e)`

= `(1)/e.log(e^-1)`

= `(1)/e.(-1)log e`

= `-(1)/e`.                 ...[∵ log e = 1]

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Chapter 2: Applications of Derivatives - Exercise 2.4 [Page 90]

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