English

The maximum value of (1x)x is ______.

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Question

The maximum value of `(1/x)^x` is ______.

Options

  • e

  • ex

  • `"e"^(1/"e")`

  • `(1/"e")^(1/"e")`

  • ee

MCQ
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Solution

The maximum value of `(1/x)^x` is `underlinebb(e^(1/e))`.

Explanation:

Let f(x) = `(1/x)^x`

Taking log on both sides, we get

log [f (x)] = `x log  1/x`

⇒ log [f (x)] = `x log x^-1`

⇒ log [f (x)] = – [x log x]

Differentiating both sides w.r.t. x, we get

`1/("f"(x)) * "f'"(x) = - [x * 1/x + log x * 1]`

= `- "f"(x) [1 + log x]`

⇒ f'(x) = `- (1/x)^x [1 + log x]`

For local maxima and local minima f'(x) = 0

`-(1/x)^x [1 + log x]` = 0

⇒ `(1/x)^x [1 + log x]`= 0

`(1/x)^x ≠ 0`

∴ 1 + log x = 0

⇒ log x = – 1

⇒ x = e–1

So, x = `1/"e"` is the stationary point.

Now f'(x) = `-(1/x)^x [1 + log x]`

f"(x) = `-[(1/x)^x (1/x) + (1 + log x) * "d"/"dx" (x)^x]`

f"(x) = `-[("e")^(1/"e") ("e") + (1 + log  1/"e") "d"/"dx" (1/"e")^(1/"e")]`

x = `1/"e"`

= `-"e"^(1/"e") 1 < 0` maxima

∴ Maximum value of the function at x = `1/"e"` is 

`"f"(1/"e") = (1/(1/"e"))^(1/"e") = "e"^(1/"e")`

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Chapter 6: Application Of Derivatives - Exercise [Page 141]

APPEARS IN

NCERT Exemplar Mathematics Exemplar [English] Class 12
Chapter 6 Application Of Derivatives
Exercise | Q 59 | Page 141

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