Advertisements
Advertisements
Question
Find the excluded values, of the following expression
`(x^2 + 6x + 8)/(x^2 + x - 2)`
Advertisements
Solution
x2 + 6x + 8 = (x + 4) (x + 2)
x2 + x – 2 = (x + 2) (x – 1)
`(x^2 + 6x + 8)/(x^2 + x - 2) = ((x + 4)(x + 2))/((x + 2)(x - 1))`
= `(x + 4)/(x - 1)`
The expression `(x + 4)/(x - 1)` is undefined
when x – 1 = 0
∵ x = 1
The excluded value is 1
APPEARS IN
RELATED QUESTIONS
Find the excluded values, of the following expression
`y/(y^2 - 25)`
Find the excluded values, of the following expression
`"t"/("t"^2 - 5"t" + 6)`
Simplify `("p"^2 - 10"p" + 21)/("p" - 7) xx ("p"^2 + "p" - 12)/("p" - 3)^2`
Simplify `(2"a"^2 + 5"a" + 3)/(2"a"^2 + 7"a" + 6) ÷ ("a"^2 + 6"a" + 5)/(-5"a"^2 - 35"a" - 50)`
If x = `("a"^2 + 3"a" - 4)/(3"a"^2 - 3)` and y = `("a"^2 + 2"a" - 8)/(2"a"^2 - 2"a" - 4)` find the value of x2y–2
Simplify `(x(x + 1))/(x - 2) + (x(1 - x))/(x - 2)`
If A = `(2x + 1)/(2x - 1)`, B = `(2x - 1)/(2x + 1)` find `1/("A" - "B") - (2"B")/("A"^2 - "B"^2)`
Iniya bought 50 kg of fruits consisting of apples and bananas. She paid twice as much per kg for the apple as she did for the banana. If Iniya bought ₹ 1800 worth of apples and ₹ 600 worth bananas, then how many kgs of each fruit did she buy?
`(3y - 3)/y ÷ (7y - 7)/(3y^2)` is
Solve `1/3` (x + y – 5) = y – z = 2x – 11 = 9 – (x + 2z)
