Advertisements
Advertisements
Question
Two farmers Thilagan and Kausigan cultivates three varieties of grains namely rice, wheat and ragi. If the sale (in ₹) of three varieties of grains by both the farmers in the month of April is given by the matrix.
`{:"April sale in" ₹)/("rice" "wheat" "ragi":}`
A = `[(500, 1000, 1500),(2500, 1500, 500)]"Thilagan"/"Kausigan"`
and the May month sale (in ₹) is exactly twice as that of the April month sale for each variety.
If the sales continue to increase in the same way in the successive months, what will be sales in the month of August?
Advertisements
Solution
If it increasing in the successive months of
May sale is 2 ...(April sale)
June sale is 4 ...(April sale)
July sale is 8 ...(April sale)
August sale is 16 ...(April sale)
Sales in the month of August
= `16[(500, 1000, 1500),(2500, 1500, 500)]`
= `[(8000, 16000, 24000),(40000, 24000, 8000)]`
APPEARS IN
RELATED QUESTIONS
Find the excluded values, of the following expression
`(x^2 + 6x + 8)/(x^2 + x - 2)`
Simplify `(x^3 - y^3)/(3x^2 + 9xy + 6y^2) xx (x^2 + 2xy + y^2)/(x^2 - y^2)`
Simplify `("b"^2 + 3"b" - 28)/("b"^2 + 4"b" + 4) ÷ ("b"^2 - 49)/("b"^2 - 5"b" - 14)`
Simplify `(x + 2)/(4"y") ÷ (x^2 - x - 6)/(12y^2)`
If a polynomial p(x) = x2 – 5x – 14 is divided by another polynomial q(x) we get `(x - 7)/(x + 2)`, find q(x)
Simplify `((2x + 1)(x - 2))/(x - 4) - ((2x^2 - 5x + 2))/(x - 4)`
`(3y - 3)/y ÷ (7y - 7)/(3y^2)` is
One hundred and fifty students are admitted to a school. They are distributed over three sections A, B and C. If 6 students are shifted from section A to section C, the sections will have equal number of students. If 4 times of students of section C exceeds the number of students of section A by the number of students in section B, find the number of students in the three sections
Reduce the given Rational expression to its lowest form
`(x^(3"a") - 8)/(x^(2"a") + 2x^"a" + 4)`
Simplify `(1/("p") + 1/("q" + "r"))/(1/"p" - 1/("q" + "r")) xx [1 + ("q"^2 + "r"^2 - "p"^2)/(2"qr")]`
