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Question
`(3y - 3)/y ÷ (7y - 7)/(3y^2)` is
Options
`(9y)/7`
`(9y^3)/((21y - 21))`
`(21y^2 - 42y + 21)/(3y^3)`
`(7(y^2 - 2y + 1))/(y^2)`
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Solution
`(9y)/7`
Explanation;
Hint: `(3y - 3)/y ÷ (7y - 7)/(3y^2)`
= `(3(y - 1))/y ÷ (7(y - 1))/(3y^2)`
= `(3(y - 1))/y xx (3y^2)/(7(y - 1))`
= `(9y)/7`
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