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Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 10

Simplify x+43x+4y×9x2-16y22x2+3x-20

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Question

Simplify `(x + 4)/(3x + 4y) xx (9x^2 - 16y^2)/(2x^2 + 3x - 20)`

Sum
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Solution

9x2 – 16y2 = (3x)2 – (4y)2

= (3x + 4y) (3x – 4y)

2x2 + 3x – 20 = 2x2 + 8x – 5x – 20

= 2x (x + 4) – 5 (x + 4)

= (x + 4) (2x – 5)

`(x + 4)/(3x + 4y) xx (9x^2 - 16y^2)/(2x^2 + 3x - 20) = ((x + 4) xx (3x + 4y)(3x - 4y))/((3x + 4y)(x + 4)(2x - 5))`

= `(3x - 4y)/(2x - 5)`

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Chapter 3: Algebra - Exercise 3.5 [Page 101]

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Samacheer Kalvi Mathematics [English] Class 10 SSLC TN Board
Chapter 3 Algebra
Exercise 3.5 | Q 2. (i) | Page 101

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