Advertisements
Advertisements
प्रश्न
Simplify `(x + 4)/(3x + 4y) xx (9x^2 - 16y^2)/(2x^2 + 3x - 20)`
Advertisements
उत्तर
9x2 – 16y2 = (3x)2 – (4y)2
= (3x + 4y) (3x – 4y)
2x2 + 3x – 20 = 2x2 + 8x – 5x – 20
= 2x (x + 4) – 5 (x + 4)
= (x + 4) (2x – 5)
`(x + 4)/(3x + 4y) xx (9x^2 - 16y^2)/(2x^2 + 3x - 20) = ((x + 4) xx (3x + 4y)(3x - 4y))/((3x + 4y)(x + 4)(2x - 5))`
= `(3x - 4y)/(2x - 5)`
APPEARS IN
संबंधित प्रश्न
Reduce the following rational expression to its lowest form
`("p"^2 - 3"p" - 40)/(2"p"^3 - 24"p"^2 + 64"p")`
Find the excluded values, of the following expression
`"t"/("t"^2 - 5"t" + 6)`
Find the excluded values, of the following expression
`(x^3 - 27)/(x^3 + x^2 - 6x)`
Simplify `("b"^2 + 3"b" - 28)/("b"^2 + 4"b" + 4) ÷ ("b"^2 - 49)/("b"^2 - 5"b" - 14)`
If a polynomial p(x) = x2 – 5x – 14 is divided by another polynomial q(x) we get `(x - 7)/(x + 2)`, find q(x)
Simplify `(x + 2)/(x + 3) + (x - 1)/(x - 2)`
If A = `(2x + 1)/(2x - 1)`, B = `(2x - 1)/(2x + 1)` find `1/("A" - "B") - (2"B")/("A"^2 - "B"^2)`
`(3y - 3)/y ÷ (7y - 7)/(3y^2)` is
Solve `1/3` (x + y – 5) = y – z = 2x – 11 = 9 – (x + 2z)
Simplify `(1/("p") + 1/("q" + "r"))/(1/"p" - 1/("q" + "r")) xx [1 + ("q"^2 + "r"^2 - "p"^2)/(2"qr")]`
