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Find the distance between the points: P(a + b, a – b) and Q(a – b, a + b)

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Question

Find the distance between the points:

P(a + b, a – b) and Q(a – b, a + b)

Sum
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Solution

P(a + b, a - b) and Q(a - b, a + b)

The given points are P(a + b, a - b) and Q(a - b, a + b)

Then (x1 = a + b, y1 = a - b) and (x2 = a - b, y2 = a + b)

PQ = `sqrt((x_2-x_1)^2 +(y_2-y_1)^2)`

= `sqrt({(a-b)-(a+b)}^2+{(a+b)-(a-b)}^2)`

= `sqrt((a-b-a-b)^2 +(a+b-a+b)^2)`

= `sqrt((-2b)^2+(2b)^2)`

= `sqrt (4b^2 +4b^2)`

= `sqrt(8b^2)`

= `sqrt(4 xx2b^2)`

= `2 sqrt(2b)` units

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Chapter 6: Coordinate Geometry - EXERCISE 6A [Page 311]

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 6 Coordinate Geometry
EXERCISE 6A | Q 1. (v) | Page 311
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