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Find the distance between the points: P(a + b, a – b) and Q(a – b, a + b)

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प्रश्न

Find the distance between the points:

P(a + b, a – b) and Q(a – b, a + b)

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उत्तर

P(a + b, a - b) and Q(a - b, a + b)

The given points are P(a + b, a - b) and Q(a - b, a + b)

Then (x1 = a + b, y1 = a - b) and (x2 = a - b, y2 = a + b)

PQ = `sqrt((x_2-x_1)^2 +(y_2-y_1)^2)`

= `sqrt({(a-b)-(a+b)}^2+{(a+b)-(a-b)}^2)`

= `sqrt((a-b-a-b)^2 +(a+b-a+b)^2)`

= `sqrt((-2b)^2+(2b)^2)`

= `sqrt (4b^2 +4b^2)`

= `sqrt(8b^2)`

= `sqrt(4 xx2b^2)`

= `2 sqrt(2b)` units

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Coordinate Geometry - EXERCISE 6A [पृष्ठ ३११]

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आर.एस. अग्रवाल Mathematics [English] Class 10
अध्याय 6 Coordinate Geometry
EXERCISE 6A | Q 1. (v) | पृष्ठ ३११
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