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Question
Find the derivative of the following function (it is to be understood that a, b, c, d, p, q, r and s are fixed non-zero constants and m and n are integers):
`1/(ax^2 + bx + c)`
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Solution
Let f(x) = `1/(ax^2 + bx + c)`
f'(x) = `([d/dx1](ax^2 + bx + c) - 1 d/dx (ax^2 + bx + c))/(ax^2 + bx + c)^2`
= `(0. (ax^2 + bx + c) - (2ax + b))/(ax^2 + bx + c)^2`
= `(-(2ax + b))/(ax^2 + bx + c)^2`
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