Advertisements
Advertisements
Question
Find the cube of: `4"p" - (1)/"p"`
Sum
Advertisements
Solution
`(4"p" - (1)/"p")^3`
= `(4"p")^3 - (1/"p")^3 - 3(4"p") (1/"p") (4"p" - 1/"p")`
= `64"p"^3 - (1)/"P"^3 - 48"p" + (12)/"p"`.
shaalaa.com
Is there an error in this question or solution?
